![x,y,z gt0 , x,y,z!=1 , lnx+lny+lnz=0` then find value of `k=x^(1/lny + 1/lnz) * y^(1/lnx + 1/l... - YouTube x,y,z gt0 , x,y,z!=1 , lnx+lny+lnz=0` then find value of `k=x^(1/lny + 1/lnz) * y^(1/lnx + 1/l... - YouTube](https://i.ytimg.com/vi/feNaSt76thE/maxresdefault.jpg)
x,y,z gt0 , x,y,z!=1 , lnx+lny+lnz=0` then find value of `k=x^(1/lny + 1/lnz) * y^(1/lnx + 1/l... - YouTube
![The domain of the function f(x)=x/(sqrt(sin(lnx)-cos(lnx))),(n in Z) is (a)(e^(2npi),e^((3n+1/2)pi)) (b) (e^((2n+1/4)pi),e^((2n+5/4)pi)) (e^((2n+1/4)pi),e^((2n-3/4)pi)) (d) none of these The domain of the function f(x)=x/(sqrt(sin(lnx)-cos(lnx))),(n in Z) is (a)(e^(2npi),e^((3n+1/2)pi)) (b) (e^((2n+1/4)pi),e^((2n+5/4)pi)) (e^((2n+1/4)pi),e^((2n-3/4)pi)) (d) none of these](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/27707_web.png)
The domain of the function f(x)=x/(sqrt(sin(lnx)-cos(lnx))),(n in Z) is (a)(e^(2npi),e^((3n+1/2)pi)) (b) (e^((2n+1/4)pi),e^((2n+5/4)pi)) (e^((2n+1/4)pi),e^((2n-3/4)pi)) (d) none of these
![If `x^[ln[y/z]].y^[ln[xz]^2].z^[ln[x/y]]=y^[4lny]` for any x gt1,y gt1 and z gt1, then which on... - YouTube If `x^[ln[y/z]].y^[ln[xz]^2].z^[ln[x/y]]=y^[4lny]` for any x gt1,y gt1 and z gt1, then which on... - YouTube](https://i.ytimg.com/vi/SvSbojF46H4/maxresdefault.jpg)